// only one led color will turn on at a time either blue or red

int led[9] = {0, 0, 0, 0, 0, 0, 0, 0, 0};

// red and blue
int ledCol[3][3][2] = {
  {{0, 1}, {1, 0}, {0, 1}},
  {{1, 0}, {0, 1}, {1, 0}},
  {{0, 1}, {1, 0}, {0, 1}}
};

byte comPins[3] = {13, 12, 11};
byte bluePins[3] = {A3, A4, A5};
byte redPins[3] = {A0, A1, A2};

void ledDrive() {
  for (int row = 0; row < 3; row++) {
    digitalWrite(comPins[row], LOW);
    for (int col = 0; col < 3; col++) {
      if (ledCol[row][col][0] == 1) {
        digitalWrite(redPins[col], HIGH);
      } else {
        digitalWrite(redPins[col], LOW);
      }
      if (ledCol[row][col][1] == 1) {
        digitalWrite(bluePins[col], HIGH);
      } else {
        digitalWrite(bluePins[col], LOW);
      }
    }delay(1);
    digitalWrite(comPins[row], HIGH);
  }
}

void setup() {
  Serial.begin(9600);
  Serial.println("");
  for (int c = 0; c < 3; c++) {
    pinMode(comPins[c], OUTPUT);
    pinMode(bluePins[c], OUTPUT);
    pinMode(redPins[c], OUTPUT);
    digitalWrite(comPins[c], HIGH);
  }
}

void loop() {
  ledDrive();
}