int redPin = 12;
int greenPin = 11;
int bluePin = 10;
int waitT = 250;

String msg = "What color do you want?(1 = R,2 = G,3 = B) ";
int choice;
int pin;
void setup() {
  // put your setup code here, to run once:
  Serial.begin(9600);


}

void loop() {
  // put your main code here, to run repeatedly:
Serial.println(msg);

Serial.print("Serial availability: ");
Serial.println(Serial.available());

while(Serial.available() == 0){

}

choice = Serial.parseInt();


/*if the serial monitor is not restarted, Serial.available() will
return 1 instead of 0 and the while loop will be skipped on even
numbered void loops. Find a better way to make Serial.available()
return 0.*/

/*Serial.end();
Serial.begin(9600);*/

while(Serial.available() != 0){
  Serial.parseInt();
}


switch(choice){
  case 1:
    pin = redPin;
    break;
  case 2:
    pin = greenPin;
    break;
  case 3:
    pin = bluePin;
    break;
}


for(int i = 0; i < 3; i++){
  digitalWrite(pin, HIGH);
  delay(waitT);
  digitalWrite(pin, LOW);
  delay(waitT);
}

delay(1000);

}