from machine import Pin
import utime
import tm1637

# Connect Keypad pins as below
col_list=[5,6,7,8]
row_list=[9,10,11,12]
 
#Set rows pin as output
for x in range(0,4):
    row_list[x]=Pin(row_list[x], Pin.OUT)
    row_list[x].value(1)
 
#Set column as input
for x in range(0,4):
    col_list[x] = Pin(col_list[x], Pin.IN, Pin.PULL_UP)
 
# Create a map between keypad buttons and chars
key_map=[["F","E","D","C"],\
         ["B","A","9","8"],\
         ["7","6","5","4"],\
         ["3","2","1","0"]]
 
def Keypad4x4Read(cols,rows):
  for r in rows:
    r.value(0)
    result=[cols[0].value(),cols[1].value(),cols[2].value(),cols[3].value()]
    if min(result)==0:
      key=key_map[int(rows.index(r))][int(result.index(0))]
      r.value(1) # manages key keept pressed
      return(key)
    r.value(1)

tm = tm1637.TM1637(clk = Pin((16)), dio = Pin((17)))
num =0

# Start the main loop
print("--- Ready to get user inputs ---")
while True:
    key=Keypad4x4Read(col_list, row_list)
    if key != None:
      print("Pressed button: "+key)
      tm.write([0, 0, 0, 0])
      tm.show(str(key))
      utime.sleep(0.3) # gives user enough time to release without having double inputs known as debounce